eolas/zk/Biconditional_Introduction.md
2024-02-16 15:19:05 +00:00

14 lines
351 B
Markdown

---
categories:
- Logic
tags: []
---
# Biconditional introduction
The biconditional means if $P$ is the case, $Q$ must be the case and if $Q$ is
the case, $P$ must be the case. Thus to introduce this operator we must
demonstrate both that $Q$ follows from $P$ and that $P$ follows from $Q$. We do
this via two sub-proofs.
![](/_img/bi-intro.png)