12 lines
328 B
Markdown
12 lines
328 B
Markdown
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tags: []
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---
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# Biconditional introduction
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The biconditional means if $P$ is the case, $Q$ must be the case and if $Q$ is
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the case, $P$ must be the case. Thus to introduce this operator we must
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demonstrate both that $Q$ follows from $P$ and that $P$ follows from $Q$. We do
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this via two sub-proofs.
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