--- tags: - Logic - propositional-logic - consistency --- ## Informal definition A set of sentences is consistent if and only if **it is possible for all the members of the set to be true at the same time**. A set of sentences is inconsistent if and only if it is not consistent. ### Demonstration The following set of sentences form an inconsistent set: ```` (1) Anyone who takes astrology seriously is a lunatic. (2) Alice is my sister and no sister of mine has a lunatic for a husband. (3) David is Alice's husband and he read's the horoscope column every morning. (4) Anyone who reads the horoscope column every morning takes astrology seriously. ```` The set is inconsistent because not all of them can be true. If (1), (3), (4) are true, (2) cannot be. If (2), (3),(4) are true, (1) cannot be. ## Formal definition > > A finite set of sentences $\Gamma$ is truth-functionally consistent if and only if there is at least one truth-assignment in which all sentences of $\Gamma$ are true. ### Informal expression ```` The book is blue or the book is brown The book is brown ```` ### Formal expression ```` {P v Q, Q} ```` ### Truth-table ```` P Q P ∨ Q Q T T T T * T F T F F T T T * F F F F ```` ## Derivation > > In terms of logical derivation, a finite $\Gamma$ of propositions is **inconsistent** in a system of derivation for propositional logic if and only if a sentence of the $P & \sim P$ is derivable from $\Gamma$. It is **consistent** just if this is not the case. In other terms, if you can derive a contradiction from the set, the set is logically inconsistent. A [contradiction](Logical%20truth%20and%20falsity.md#logical-falsity) contradiction has very important consequences for reasoning because if a set of propositions is inconsistent, every and all other propositions are derivable from that set. ![proofs-drawio-Page-5.drawio 3.png](../img/proofs-drawio-Page-5.drawio%203.png) *A demonstration of the the consequences of deriving a contradiction in a sequence of reasoning.* Here we want to derive some proposition $Q$. If we can derive a contradiction from its negation as an assumption then, by the [negation elimination](Negation%20Elimination.md) rule, we can assert $Q$. This is why contradictions should be avoided in arguments, they 'prove' everything which, by association, undermines any particular premise you are trying to assert.