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@ -43,8 +43,6 @@ In the example above, `aValue` could be edited in instantiations of the class. G
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## Object modules
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---
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If you want to use an object instead of a class, you have to take greater care to ensure that the objects are not overwritable. **Also you cannot use the `#` modifier to make properties private.**
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- Use getters and setters for updating and retrieving values
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@ -6,4 +6,43 @@ tags:
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# Sliding window
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Whereas the [multiple pointer](Multiple_pointers.md) pattern works by keeping two array indices running at once and comparing their values, the sliding
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Whereas the [multiple pointer](Multiple_pointers.md) pattern works by keeping two array indices running at once and comparing their values on each iteration, the sliding window
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has a running value (the 'window') that is updated at each iteration and which compares itself against its most recent previous value.
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This is what makes it 'sliding': the value isn't constant, it changes (or doesn't) based on what it was previously.
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## Example: maximum sum of sub-array
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We create a function that takes an array and a sub-array length _n_. The objective is to find the maximum value that can be created by summing _n_ elements of the array. It moves through the array, summing by _n_ keeping track of the highest sum value so far and the current sum value. At the end it should return the highest possible sum value.
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Here we do this for a sub-array of length 2:
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```ts
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function maxSubarraySum(arr, subArrLength) {
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let maxSum = 0; // Largest sum value so far
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let tempSum = 0; // Current sum value
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// Establish the first 'maxSum'
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// At the beginning this will just be the sum of the first two array elements
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for (let i = 0; i < subArrLength; i++) {
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maxSum += arr[i];
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}
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// Map temporary sum to maxSum
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// Accordingly, as we have only mapped the first sub-array, the max sum will be the same
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// as the current sum
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tempSum = maxSum;
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// Move through the array one element at a time (`i++`) via a window starting from the element that is equal to `subArrLength`
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// The first sum calculation is already taken care of in the earlier loop and stored in `maxSum`, so we don't have to worry about missing the elements in indices less than subArrLength
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for (let i = subArrLength; i < arr.length; i++) {
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// Temp sum becomes a moveable window value equal to the subtraction of the previous element and the addition of next element in line
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tempSum = tempSum - arr[i - subArrLength] + arr[i];
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// Max sum is redefined as the largest subArrLengthber between the previous highest and the current value of tempSum
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maxSum = Math.max(maxSum, tempSum);
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}
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return maxSum;
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}
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console.log(maxSubarraySum([100, 200, 300, 400], 2)); // 700
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```
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