diff --git a/Mathematics/Prealgebra/Add_Subtract_Fractions.md b/Mathematics/Prealgebra/Add_Subtract_Fractions.md index 8234a53..ce45739 100644 --- a/Mathematics/Prealgebra/Add_Subtract_Fractions.md +++ b/Mathematics/Prealgebra/Add_Subtract_Fractions.md @@ -36,6 +36,94 @@ $$ * Add/subtract * Reduce -Demonstration: $\frac{4}{9} + \frac{1}{6}$ : -The lowest common denominator is **the smallest number divisible by both of the denominators of the fractions without remainder**. + +### Lowest common denominator and lowest common multiple + +Given the symmetry between [factors and divisors](/Mathematics/Prealgebra/Factors_and_divisors.md) these properties are related. Note however that the LCM is more generic: it applies to any set of numbers not just fractions. Whereas the LCD is explicitly to do with fractions (hence 'denominator'). + + +* For two fractions $a, b$ (or a set), the LCD is the smallest number divisble by both the denominator of $a$ and the denominator of $b$ (or each member of the set). + + +* For two fractions $a, b$ (or a set), the LCM is the smallest number that is a multiple of the denominator of $a$ and the denominator of $b$ (or each member of the set). + +In order to find the LCM of the set $\{12, 16\}$ we list the multiples of both: +$$ +12, 24, 36, 48 \\ +16, 32, 48 +$$ + +Until we identify the smallest number common to both lists. In this case it is 48. Thus the LCM of 12 and 16 is 48. + +The relationship between LCM and LCD is that _the least common denominator is the least common multiple of the fractions' denomintors_. + + + +### Demonstration: addition +We can now use this to calculate the addition of two fractions without common denominators: $\frac{4}{9} + \frac{1}{6}$. + +First identify the common multiples of 9 and 6: + +$$ +9, 18, ... \\ +6, 12, 18, ... +$$ + +The least common multiple is 18. +We then think: what do we need to multiply each denominator by to get 18? + +In the case of the first fraction ($\frac{4}{9}$) it is 2: + +$$ + \frac{4}{9 \cdot 2} = \frac{4}{18} +$$ + +But what we do to the denominator, we must also do to the numerator, hence: + +$$ + \frac{4 \cdot 2}{9 \cdot 2} = \frac{8}{18} +$$ + +We then do the same to the second fraction ($\frac{1}{6}$). We need to multiply its denominator by 3 to get 18 and we apply this also to the numerator. + +$$ + \frac{1 \cdot 3}{6 \cdot 3} = \frac{3}{18} +$$ + +We now have two fractions that share a common denominator so we can sum: + +$$ + \frac{8}{18} + \frac{3}{18} = \frac{11}{18} +$$ + +### Demonstration: subtraction + +Calculate: + +$$ + \frac{3}{5} - \frac{2}{3} +$$ + +Once again we need to find the least common denominator for the two fractions. We start by listing the common multiples for the two denominators 5 and 3: + +$$ +5, 10, 15, ... \\ +3, 6, 9, 12, 15,... +$$ + +The lowest common multiple is 15. From the first fraction we get 15 by multiplying by 3. With the second fraction we get 15 by multiplying by 5. Thus: + +$$ + \frac{3 \cdot 3}{5 \cdot 3} = \frac{9}{15} +$$ + +$$ + \frac{2 \cdot 5}{3 \cdot 5} = \frac{10}{15} +$$ + +We can now carry out the subtraction: + +$$ + \frac{9}{15} - \frac{10}{15} = -\frac{1}{15} +$$ diff --git a/Mathematics/Prealgebra/Least_common_denominator.md b/Mathematics/Prealgebra/Least_common_denominator.md deleted file mode 100644 index e69de29..0000000 diff --git a/pdf/Algorithmic_complexity.pdf b/pdf/Algorithmic_complexity.pdf index 3cb41f0..4bbe665 100644 Binary files a/pdf/Algorithmic_complexity.pdf and b/pdf/Algorithmic_complexity.pdf differ diff --git a/pdf/Arrays.pdf b/pdf/Arrays.pdf index 55bc46f..f4c5364 100644 Binary files a/pdf/Arrays.pdf and b/pdf/Arrays.pdf differ diff --git a/pdf/Assembly_programs.pdf b/pdf/Assembly_programs.pdf index 43631a7..8048f49 100644 Binary files a/pdf/Assembly_programs.pdf and b/pdf/Assembly_programs.pdf differ diff --git a/pdf/Atomic_and_molecular_sentences.pdf b/pdf/Atomic_and_molecular_sentences.pdf index 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