eolas/Logic/Proofs/Biconditional_Elimination.md

---
categories:
  - Mathematics
tags: [logic]
---

Give that the biconditional means that if $P$ is the case, $Q$ is the case and if $Q$ is the case, $P$ must be the case, if we have $P \equiv Q$ and $P$, we can derive $Q$ and vice versa.

![biconditional-elim.png](../img/biconditional-elim.png)
Initial commit, pure MD 2022-04-23 13:26:53 +01:00			`---`
Last Sync: 2022-08-20 12:30:04 2022-08-20 12:30:04 +01:00			`categories:`
Reindexing 2022-09-06 13:26:44 +01:00			`- Mathematics`
			`tags: [logic]`
Initial commit, pure MD 2022-04-23 13:26:53 +01:00			`---`

			`Give that the biconditional means that if $P$ is the case, $Q$ is the case and if $Q$ is the case, $P$ must be the case, if we have $P \equiv Q$ and $P$, we can derive $Q$ and vice versa.`

			`![biconditional-elim.png](../img/biconditional-elim.png)`