eolas/Logic/Propositional_logic/Boolean_algebra.md

121 lines
3.5 KiB
Markdown
Raw Normal View History

2022-12-18 13:00:05 +00:00
---
categories:
- Logic
tags: [propositional-logic, algebra]
---
# Boolean algebra
2022-12-18 14:30:04 +00:00
## Algebraic laws
2022-12-18 13:00:05 +00:00
Many of the laws that obtain in the mathematical realm of algebra also obtain for Boolean expressions.
2022-12-18 14:30:04 +00:00
### The Commutative Law
2022-12-18 13:00:05 +00:00
$$
x \land y = y \land x \\
$$
$$
x \lor y = y \lor x
$$
2022-12-18 13:30:05 +00:00
Compare the [Commutative Law](/Mathematics/Prealgebra/Whole_numbers.md#the-commutative-property) in the context of arithmetic.
2022-12-18 14:30:04 +00:00
### The Associative Law
2022-12-18 13:30:05 +00:00
$$
x \land (y \land z) = (x \land y) \land z
$$
$$
x \lor (y \lor z) = (x \lor y) \lor z
$$
Compare the [Associative Law](/Mathematics/Prealgebra/Whole_numbers.md#the-associative-property) in the context of arithmetic.
2022-12-18 14:30:04 +00:00
### The Distributive Law
2022-12-18 13:30:05 +00:00
$$
x \land (y \lor z) = (x \land y) \lor (x \land z)
$$
$$
x \lor (y \land z) = (x \lor y) \land (x \lor z)
$$
Compare for instance how this applies in the case of [multiplication](/Mathematics/Prealgebra/Distributivity.md):
$$
a \cdot (b + c) = a \cdot b + a \cdot c
$$
In addition we have [DeMorgan's Laws](/Logic/Laws_and_theorems.md/DeMorgan's_Laws.md) which express the relationship that obtains between the negations of conjunctive and disjunctive expressions
2022-12-18 14:30:04 +00:00
## Applying the laws to simplify complex Boolean expressions
Say we have the following expression:
$$
\lnot(\lnot(x) \land \lnot (x \lor y))
$$
We can employ DeMorgan's Laws to convert the second conjunct to a different form:
$$
\lnot (x \lor x) = \lnot x \land \lnot y
$$
So now we have:
$$
\lnot(\lnot(x) \land (\lnot x \land \lnot y ))
$$
As we have now have an expression of the form _P and (Q and R)_ we can apply the Distributive Law to simplify the brackets (_P and Q and R_):
$$
\lnot( \lnot(x) \land \lnot(x) \land \lnot(y))
$$
Notice that we are repeating ourselves in this reformulation. We have $\lnot(x) \land \lnot(x)$ but this is just the same $\lnot(x)$ by the principle of **idempotence**. So we can reduce to:
$$
\lnot(\lnot(x) \land \lnot(y))
$$
This gives our expression the form of the first DeMorgan Law ($\lnot (P \land Q)$), thus we can apply the law ($\lnot P \lor \lnot Q$) to get:
$$
\lnot(\lnot(x)) \lor \lnot(\lnot(y))
$$
2022-12-18 19:00:05 +00:00
Of course now we have two double negatives. We can apply the double negation law to get:
2022-12-18 14:30:04 +00:00
$$
x \lor y
$$
2022-12-18 19:00:05 +00:00
### Truth table
Whenever we simplify an algebraic expression the value of the resulting expression should match that of the complex expression. We can demonstrate this with a truth table:
| $x$ | $y$ | $\lnot(\lnot(x) \land \lnot (x \lor y))$ | $x \lor y$ |
| --- | --- | ---------------------------------------- | ---------- |
| 0 | 0 | 0 | 0 |
| 0 | 1 | 1 | 1 |
| 1 | 0 | 1 | 1 |
| 1 | 1 | 1 | 1 |
### Significance for computer architecture
The fact that we can take a complex Boolean function and reduce it to a simpler formulation has great significance for the development of computer architectures, specifically [logic gates](/Electronics_and_Hardware/Digital_circuits/Logic_gates.md). It would be rather resource intensive and inefficient to create a gate that is representative of the complex function. Whereas the simplified version only requires a single [OR gate](/Electronics_and_Hardware/Digital_circuits/Logic_gates.md#or-gate)
2022-12-18 14:30:04 +00:00
// TO DO:
- Use truth tables to show equivalence
- Explicitly add implicit laws
- Link to deductive rules
- Link to digital circuits and NANDs as universal gates